Biology 120 Lab Exam 2 Review Student Learning Services and Biology 120 Peer Mentors Thursday, November 22, 2018 7:00 pm Main Rooms: Arts 263, 217, 202, 212 Important note: This review was written by your Biology Peer Mentors (not the lab instructors)! It is designed to help you test yourself on topics and concepts covered in lab and should not in any way be considered a preview of the actual exam. You are encouraged to attempt to complete this review without the lab manual, textbook, your notes, or the internet. The peer mentors are available while you are working to help you with any questions that cause you difficulties. If you find that the room is too noisy for you to concentrate, Room 213 is a designated Quiet Work Space. Structured Study Session Information (Term 1, 2018-19) Mondays 2:30-3:50pm Arts 213 (Cameron) Tuesdays 8:30-9:50am Murray G3 (Kelly) Wednesdays 10:00-11:20am Murray G3 (Mars) Wednesdays 5:00-6:20pm Murray G3 (Sergey) Thursdays 2:30-3:50pm Murray 145 (Apurv) Thursdays 4:30-5:50pm Murray 102 (Justin) Friday 1:30-2:50pm Murray G3 (Judy) References Buchanan, F. (2018). Inheritance Patterns. Lecture. ANSCI 313. January 3, 2018. Schmutz, S. M. (2004, February 13). General Genetics References. Retrieved March 21, 2018, from http://homepage.usask.ca/~schmutz/cowboys.html#references Schmutz, S. M. (2016, May 7). Genetics of Coat Color and Type in Dogs. Retrieved March 21, 2018, from http://homepage.usask.ca/~schmutz/dogcolors.html Last updated: 2018-11-21 8:30 AM
2 Spot Test 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15.
3 Short Answer 1. Fill in the blanks. a. In ferns, cells inside the undergo meiosis to produce. b. The fern gametophyte can also be called a. c. In animals two haploid cells called combine together to form a diploid cell called a in the process known as. d. Crossing over occurs during of meiosis and the region where this occurs is called the. e. Female mice produce gametes called in their and male mice produce gametes called in their. 2. The Manx cat is a breed of domestic cats that has a shorter than normal tail. The short tail mutation is dominant to normal tail, but the short tail mutation is homozygous lethal and usually results in miscarriages. A male Manx cat is bred with one Manx female and one normal female. What are the expected genotypic and phenotypic ratios of the kittens born for each cat? Show your work.
4 3. Oculocutaneous albinism and α-mannosidosis are both genetic disorders that can affect Angus cows. Both disorders are autosomal recessive and are found on different chromosomes. Oculocutaneous albinism causes the animals affected to have white eyes. Animals affected with α-mannosidosis, caused by the lack of the enzyme α-d-mannosidase in the lysosome, are characterized by their failure to thrive and they die within the first year (i.e., before they are able to reproduce). A farmer has one bull and 48 cows. All of the animals are heterozygous for both traits. a. Draw the Punnet Square for the cross. b. What is the expected phenotypic ratio if all of the cows have a calf? c. How many calves will be born with white eyes?
5 4. White Heifer Disease (WHD) is a congenital reproductive abnormality in white female offspring (heifers) in certain breeds of cattle, such as Belgian Blue and Shorthorn. WHD is actually the result of two genes- white fur colour is inherited as an autosomal recessive trait (h), which is linked with an autosomal recessive gene that causes defects in the female reproductive tract (r). a. Draw a Punnett square for a cow heterozygous for both traits being bred to a bull that is also heterozygous for both. Assume no crossing over occurs. b. What is the genotypic frequency of this cross? c. If the heterozygous bull and the heterozygous cow had only female offspring what proportion would have normal reproductive systems? d. University of Saskatchewan geneticists discovered that the genes for coat colour and reproductive system are 1 map unit apart. If 200 heterozygous cows were bred to a homozygous recessive bull, how many calves would have white coats and normal reproductive systems? Assume that all offspring are female, and that each cow has only one calf. e. Draw a chromosome diagram for a cell of the bull in Anaphase I of Meiosis. Assume that no crossing over occurs.
6 5. Another genetic disease affecting Belgian Blue cattle is double muscling. It is caused by a single gene mutation that reduces or eliminates the activity of the myostatin protein. Use D to represent the allele responsible for the normal phenotype and d to represent the allele leading to the double muscling phenotype. A Belgian Blue breeder kept track of her herd using a pedigree chart. a. Based on the pedigree, is this likely a sex-linked trait? b. Give the genotypes for each of the following individuals: 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. c. What proportion of the offspring in the third generation are heterozygous? 6. In domestic cats, an orange coat colour is caused by an X-linked gene that is dominant to a black coat colour. a. An orange female cat had a litter of 9 kittens: 5 orange females, 2 orange males, and 2 black males. What is the genotype of the mother cat? b. You have two male cats that could have sired this litter of kittens. One is orange and one is black. Is it possible to tell which one of these cats is the father based on the phenotypes of the kittens? If so, which was most likely the sire?
7 7. Domestic cats can have unique phenotypes. One such phenotype is heterochromia; that is when the cat s eyes are two different colours. Another unique phenotype that can occur in cats is called polydactyly; that means that the cat has an extra digit on each of its paws. A female cat that was homozygous normal for both traits had a litter of kittens sired by a male cat that was homozygous for both heterochromia and polydactyly. All of the cats in the litter had eyes that were different colours and extra digits. a. Is the gene for polydactyly X-linked or autosomal? Is the gene for heterochromia X-linked or autosomal? b. Is the allele for polydactyly dominant or recessive? Is the allele for heterochromia dominant or recessive? Mittens was a polydactyl cat with heterochromia. Her mother was a normal cat in regards to both eye colour and number of digits. Mittens had kittens with a cat named Boots, who had the normal number of digits and eyes of the same colour. c. What is Boots genotype? d. What is the genotype of Mittens mother? e. What is Mittens genotype? f. If the genes for polydactyly and heterochromia are 18 map units apart, what is the expected phenotypic ratio of their offspring? g. Draw a chromosome diagram for Mittens cell in Telophase II of Meiosis. Assume no crossing over has occurred.
8 8. Circle the material best suited for DNA extraction and explain why: Urine Hair Red Blood Cells 9. What role do these solutions have in the DNA extraction you performed? a. Sports drink: b. Detergent: c. 70% ethanol: 10. What does PCR stand for? 11. What are the four ingredients required for PCR? 12. Describe the three steps in the PCR cycle: a. b. c.
9 13. What does Taq polymerase do? 14. What is a thermal cycler? 15. EcoRI is a type of and recognizes/cuts the DNA sequence. 16. What is gel electrophoresis? 17. Gels are made of, which is a polysaccharide derived from. 18. DNA is charged, because of its backbone, which means that DNA will migrate towards the electrode. 19. fragments travel farther than fragments. 20. Which stain can be visualized under white light?. Which stain can only be visualized under UV light? 21. What is the purpose of the ladder in gel electrophoresis?
10 22. Use the following gel to put the sample numbers in order from smallest fragment to largest. Ladder 1 2 3 4 23. Application Question: Labrador Retrievers come in three major coat colours: black, chocolate (brown), and yellow. These three coat colours are determined by mutations in the MC1R (melanocortin receptor 1) and the TYRP1 (tyrosinase related protein 1) genes. The TYRP1 gene has two different alleles. B gives the black phenotype, b gives the brown phenotype. MC1R also has two different alleles. E allows either the black or the brown phenotype to be shown, e only allows the yellow phenotype to be shown. In order to determine the coat colour for a dog, two different gels need to be run. One gel will be run with DNA that is cut with a restriction enzyme to determine which MC1R allele is present and the other gel is run with DNA that is cut with a restriction enzyme to determine the TYRP1 allele present. The restriction enzyme used for the MC1R gel will cut the e allele but not the E allele. The restriction enzyme used for the TYRP1 will cut the b allele but not the B allele. If all the dogs are homozygous at both traits determine the coat colour of each of the four dogs below. MC1R TYRP1 Ladder 1 2 3 4 Ladder 1 2 3 4